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5.6.1 Parallel Block Statements

1/5
A parallel_block_statement comprises two or more sequence_of_statements separated by and where each represents an independent activity that is intended to proceed concurrently with the others.

Syntax

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parallel_block_statement ::= 
    parallel [(chunk_specification)] [aspect_specificationdo
       sequence_of_statements
    and
       sequence_of_statements
   {and
       sequence_of_statements}
    end do;
3/5
The chunk_specification, if any, of a parallel_block_statement shall be an integer_simple_expression.

Dynamic Semantics

4/5
For the execution of a parallel_block_statement, the chunk_specification and the aspect_specification, if any, are elaborated in an arbitrary order. After elaborating the chunk_specification, if any, a check is made that the determined maximum number of chunks is greater than zero. If this check fails, Program_Error is raised.
5/5
Then, the various sequence_of_statements are grouped into one or more chunks, each with its own logical thread of control (see Clause 9), up to the maximum number of chunks specified by the chunk_specification, if any. Within each chunk every sequence_of_statements of the chunk is executed in turn, in an arbitrary order. The parallel_block_statement is complete once every one of the sequence_of_statements has completed, either by reaching the end of its execution, or due to a transfer of control out of the construct by one of the sequence_of_statements (see 5.1).

Examples

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Example of a parallel block used to walk a binary tree in parallel:
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procedure Traverse (T : Expr_Ptr) is -- see 3.9.1
begin
   if T /= null and then
      T.all in Binary_Operation'Class -- see 3.9.1
   then -- recurse down the binary tree
      parallel do
         Traverse (T.Left);
      and
         Traverse (T.Right);
      and
         Ada.Text_IO.Put_Line
            ("Processing " & Ada.Tags.Expanded_Name (T'Tag));
      end do;
   end if;
end Traverse;
8/5
Example of a parallel block used to search two halves of a string in parallel:
9/5
function Search (S : String; Char : Character) return Boolean is
begin
   if S'Length <= 1000 then
       -- Sequential scan
       return (for some C of S => C = Char);
   else
       -- Parallel divide and conquer
       declare
          Mid : constant Positive := S'First + S'Length/2 - 1;
       begin
          parallel do
             for C of S(S'First .. Mid) loop
                if C = Char then
                   return True;  -- Terminates enclosing do
                end if;
             end loop;
          and
             for C of S(Mid + 1 .. S'Last) loop
                if C = Char then
                   return True;  -- Terminates enclosing do
                end if;
             end loop;
          end do;
          -- Not found
          return False;
       end;
   end if;
end Search;

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